my turn to rant
Thread Starter
Joined: Sep 2006
Posts: 979
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From: Brookings, SD
RE: my turn to rant
ORIGINAL: FFCBRf4i
Interestingly enough, you’re correct…to a certain extent; it’s not exactly that easy. Newton’s Second Law states F=MA. (Sum of All) F = MA
Okay, so both crates are accelerating at 1.8 m/s^2, so the sum of all the forces on each of the crates should equal to the mass of the crates * 1
The FIRST crate, it has 2 forces on it:
1. Gravity in the down direction with force = m*g
2. Tension in the cable in the up direction with force T (which is unknown at the moment).
[Let up be positive and down be negative]
Sum of all forces:
-m*g + T = 1 * m
T = m * (g+1) = 187 * (9.8+1) = 2019.6 N
The SECOND crate, it has 3 forces on it:
1. Gravity in the down direction.
2. Tension in cable connecting this crate to the first, in the down direction as well.
3. Tension in the cable connecting this crate to the helicopter in the up direction.
-m*g - 2019.6 + T2 = 1 * m
T2 = m * (g+1) +2019.6 = I’ll let you work that out
N is for Newtons if you haven't figured that out yet. BTW you should have if you're a physics student haha.
I think I did that right, but I'm too lazy to check. Good enough to get you started right?
...And to answer your future questions: YES, I'm asian...gosh....[sm=smiley23.gif]
ORIGINAL: telgren
A helicopter is lifting two crates simultaneously. One crate with a mass of 187 kg is attached to the helicopter by cable A. The second crate with a mass of 68 kg is hanging below the first crate and attached to the first crate by cable B. As the helicopter accelerates upward at a rate of 1.8 m/s2, what is the tension in each of the two cables?
ORIGINAL: havoc_on_2_wheels
so by using F=MxA the tension would be 459n if M= 255 k and A= 1.8 m/s2
i could be wrong and i probably am lol
so by using F=MxA the tension would be 459n if M= 255 k and A= 1.8 m/s2
i could be wrong and i probably am lol
Okay, so both crates are accelerating at 1.8 m/s^2, so the sum of all the forces on each of the crates should equal to the mass of the crates * 1
The FIRST crate, it has 2 forces on it:
1. Gravity in the down direction with force = m*g
2. Tension in the cable in the up direction with force T (which is unknown at the moment).
[Let up be positive and down be negative]
Sum of all forces:
-m*g + T = 1 * m
T = m * (g+1) = 187 * (9.8+1) = 2019.6 N
The SECOND crate, it has 3 forces on it:
1. Gravity in the down direction.
2. Tension in cable connecting this crate to the first, in the down direction as well.
3. Tension in the cable connecting this crate to the helicopter in the up direction.
-m*g - 2019.6 + T2 = 1 * m
T2 = m * (g+1) +2019.6 = I’ll let you work that out
N is for Newtons if you haven't figured that out yet. BTW you should have if you're a physics student haha.
I think I did that right, but I'm too lazy to check. Good enough to get you started right?
...And to answer your future questions: YES, I'm asian...gosh....[sm=smiley23.gif]
Senior Member
Joined: Jul 2006
Posts: 1,668
Likes: 1
From: Columbus, Ohio
RE: my turn to rant
ORIGINAL: telgren
You cheater, you copied that off a website. I know you did because thats how I solved my problem too!
ORIGINAL: FFCBRf4i
Interestingly enough, you’re correct…to a certain extent; it’s not exactly that easy. Newton’s Second Law states F=MA. (Sum of All) F = MA
Okay, so both crates are accelerating at 1.8 m/s^2, so the sum of all the forces on each of the crates should equal to the mass of the crates * 1
The FIRST crate, it has 2 forces on it:
1. Gravity in the down direction with force = m*g
2. Tension in the cable in the up direction with force T (which is unknown at the moment).
[Let up be positive and down be negative]
Sum of all forces:
-m*g + T = 1 * m
T = m * (g+1) = 187 * (9.8+1) = 2019.6 N
The SECOND crate, it has 3 forces on it:
1. Gravity in the down direction.
2. Tension in cable connecting this crate to the first, in the down direction as well.
3. Tension in the cable connecting this crate to the helicopter in the up direction.
-m*g - 2019.6 + T2 = 1 * m
T2 = m * (g+1) +2019.6 = I’ll let you work that out
N is for Newtons if you haven't figured that out yet. BTW you should have if you're a physics student haha.
I think I did that right, but I'm too lazy to check. Good enough to get you started right?
...And to answer your future questions: YES, I'm asian...gosh....[sm=smiley23.gif]
ORIGINAL: telgren
A helicopter is lifting two crates simultaneously. One crate with a mass of 187 kg is attached to the helicopter by cable A. The second crate with a mass of 68 kg is hanging below the first crate and attached to the first crate by cable B. As the helicopter accelerates upward at a rate of 1.8 m/s2, what is the tension in each of the two cables?
ORIGINAL: havoc_on_2_wheels
so by using F=MxA the tension would be 459n if M= 255 k and A= 1.8 m/s2
i could be wrong and i probably am lol
so by using F=MxA the tension would be 459n if M= 255 k and A= 1.8 m/s2
i could be wrong and i probably am lol
Okay, so both crates are accelerating at 1.8 m/s^2, so the sum of all the forces on each of the crates should equal to the mass of the crates * 1
The FIRST crate, it has 2 forces on it:
1. Gravity in the down direction with force = m*g
2. Tension in the cable in the up direction with force T (which is unknown at the moment).
[Let up be positive and down be negative]
Sum of all forces:
-m*g + T = 1 * m
T = m * (g+1) = 187 * (9.8+1) = 2019.6 N
The SECOND crate, it has 3 forces on it:
1. Gravity in the down direction.
2. Tension in cable connecting this crate to the first, in the down direction as well.
3. Tension in the cable connecting this crate to the helicopter in the up direction.
-m*g - 2019.6 + T2 = 1 * m
T2 = m * (g+1) +2019.6 = I’ll let you work that out
N is for Newtons if you haven't figured that out yet. BTW you should have if you're a physics student haha.
I think I did that right, but I'm too lazy to check. Good enough to get you started right?
...And to answer your future questions: YES, I'm asian...gosh....[sm=smiley23.gif]
Not exactly cheating.
Utilizing the tools and resources that are available.
Retired Moderator ans All Around Good Guy
Joined: Jun 2006
Posts: 4,859
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RE: my turn to rant
hey telgren were u calling ME a cheater or FFCBRF4I? lol sorry its still early and i didnt get much sleep last night 
... and what was the answer to your physics problem ?
btw and yes i know you werent seriosuly calling either of us cheaters just givin a hard time ... i hope hahah
... and what was the answer to your physics problem ? btw and yes i know you werent seriosuly calling either of us cheaters just givin a hard time ... i hope hahah
Thread Starter
Joined: Sep 2006
Posts: 979
Likes: 0
From: Brookings, SD
RE: my turn to rant
ORIGINAL: havoc_on_2_wheels
^ this is exactly why i hated physics ! well that and chem and math in general lol i just slept with the TA and got all the tests . damn that girl was freaky in bed too
^ this is exactly why i hated physics ! well that and chem and math in general lol i just slept with the TA and got all the tests . damn that girl was freaky in bed too
Senior Member
Joined: Jun 2006
Posts: 696
Likes: 0
From: TN
RE: my turn to rant
[quote]ORIGINAL: KidCr3nshaw
rof*****....that was so unexpected...haha
ORIGINAL: telgren
Jello.
A helicopter is lifting two crates simultaneously. One crate with a mass of 187 kg is attached to the helicopter by cable A. The second crate with a mass of 68 kg is hanging below the first crate and attached to the first crate by cable B. As the helicopter accelerates upward at a rate of 1.8 m/s2, what is the tension in each of the two cables?
Thread Starter
Joined: Sep 2006
Posts: 979
Likes: 0
From: Brookings, SD
RE: my turn to rant
ORIGINAL: havoc_on_2_wheels
hey telgren were u calling ME a cheater or FFCBRF4I? lol sorry its still early and i didnt get much sleep last night... and what was the answer to your physics problem ?
btw and yes i know you werent seriosuly calling either of us cheaters just givin a hard time ... i hope hahah
hey telgren were u calling ME a cheater or FFCBRF4I? lol sorry its still early and i didnt get much sleep last night
... and what was the answer to your physics problem ? btw and yes i know you werent seriosuly calling either of us cheaters just givin a hard time ... i hope hahah
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