Physics Help
#1
Physics Help
Ok...so I'm doing a physics problem for homewrk and a part of this question I can't figure out.
A professional skier reaches a speed of 37 m/s on a 24 degree ski slope. Ignoring friction, what was the minimum distance along the slope the skier would have had to travel, starting from rest?
How do I get acceleration with gravity and the 24 degree slope?
A professional skier reaches a speed of 37 m/s on a 24 degree ski slope. Ignoring friction, what was the minimum distance along the slope the skier would have had to travel, starting from rest?
How do I get acceleration with gravity and the 24 degree slope?
#2
RE: Physics Help
Instead of a skier going down a slope, turn the problem into a box down a ramp at 24 degrees. The box has one force acting on it, gravity straight down. Change your coordinate system for ths problem. The X-axis should be parallel to the ramp and the Y-axis should be perpendicular to the ramp. The force of gravity will be between the new X and Y axis. Split this force up into two components, one along the X and one along the Y. Do the trig to solve for the acceleration in the X direction. I think the answer is ax = 9.8*sin(24) but its been a year since I've been in Physics.
#4
#9
RE: Physics Help
There are often many ways to solve a problem. I didn't think of using the conservation of energy. You will need to do mgh1 = mgh2 + .5mv^2. You will have to solve for h2 than use trig to find the distance. Probably the easier/faster way to solve the problem, but thats the first solution I came up with.
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