Hey guys, went down on my 99 cbr 600f4, sheared the left peg and the shifter off. i am about to buy replacement parts, but i cannont seem to understand how the shifter connects to the peg mount. from what i understand the shifter arm connects to the pedal mount at the hole just infront of the peg itself, but the diagrams do not show any kind of bolt that connects and allows the shifter arm to pivot from the peg mount. can someone please explain this to me? thank you

 

I'm thinking that it's item #8 here on the frame diagram. There are 2 of them, which would make sense for the brake lever and shifter linkage.

 

#8 holds up the rear of the fairing. The part that you are talking about is built into the rearset. I will continue too look for a photo but I could have sworn it was part of the unit. I have woodcraft ones so I cant just look.

 

OK fine, I can take a hint. I went to my garage 30' away and looked at it... LOL. You're right, it's built into it. Items #16, #13, and #12 are what hold it on.