Hey guys, bought an old 96 F3 from a guy. It had two bent rims on it and after I got it home, I realized there were no front or rear wheel spacers on it. Bought some used rims on ebay. Also was able to find a cheap set of rears on ebay, but fronts are tough to find at a reasonable price.

Since they are both the same diameter (inside and out) I figured I'd just remove the middle spacer from my bent rear wheel and cut it up to the correct widths rather than spending the $20 for the set from the dealer.

Problem is, I don't know how wide they should be.

Does anyone know how wide these things are supposed to be? I know one is wider than the other.

Any help would be much appreciated.

Thanks!

 

if you give me the specs i can spin a set on a lathe for ya

I made a set of captive spacers for my bike
here are just a few things i made
choose to cut a set of aluminum ones

 

Wow those turned out nice. I wish I had the dimensions. I might just have to tear down my other f3's front end and measure them...

 

Ok guys, I pulled the front wheel off my 97 F3 and measured the wheel spacers. The one on the brake lever side of the wheel is 22mm and the one on the clutch lever side is 15mm. Hopefully this helps someone else in the future cuz I was not able to find these dimensions anywhere else on the net.

I made my own by just taking the middle spacer out of a bent up rear wheel (which matched the inside diameter and outside diameter of the spacers), marked it all the way around from each end the 22mm and 15mm, cut at the lines with an angle grinder with a cutting abraisive wheel on it, then ground the two spacers to their final width on my bench grinder.

btw, there is also a center spacer inside the front wheel that could be cut up if you happen to have one of those laying around instead of a rear wheel.

Saved myself $30.

 

Also, as far as dimensions go, i.d. = 20mm and o.d. = 30mm